Optimal. Leaf size=116 \[ \frac{a^2 \tan ^3(c+d x)}{3 d}-\frac{a^2 \tan (c+d x)}{d}+a^2 x+\frac{3 a b \tanh ^{-1}(\sin (c+d x))}{4 d}+\frac{a b \tan ^3(c+d x) \sec (c+d x)}{2 d}-\frac{3 a b \tan (c+d x) \sec (c+d x)}{4 d}+\frac{b^2 \tan ^5(c+d x)}{5 d} \]
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Rubi [A] time = 0.152166, antiderivative size = 116, normalized size of antiderivative = 1., number of steps used = 10, number of rules used = 7, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333, Rules used = {3886, 3473, 8, 2611, 3770, 2607, 30} \[ \frac{a^2 \tan ^3(c+d x)}{3 d}-\frac{a^2 \tan (c+d x)}{d}+a^2 x+\frac{3 a b \tanh ^{-1}(\sin (c+d x))}{4 d}+\frac{a b \tan ^3(c+d x) \sec (c+d x)}{2 d}-\frac{3 a b \tan (c+d x) \sec (c+d x)}{4 d}+\frac{b^2 \tan ^5(c+d x)}{5 d} \]
Antiderivative was successfully verified.
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Rule 3886
Rule 3473
Rule 8
Rule 2611
Rule 3770
Rule 2607
Rule 30
Rubi steps
\begin{align*} \int (a+b \sec (c+d x))^2 \tan ^4(c+d x) \, dx &=\int \left (a^2 \tan ^4(c+d x)+2 a b \sec (c+d x) \tan ^4(c+d x)+b^2 \sec ^2(c+d x) \tan ^4(c+d x)\right ) \, dx\\ &=a^2 \int \tan ^4(c+d x) \, dx+(2 a b) \int \sec (c+d x) \tan ^4(c+d x) \, dx+b^2 \int \sec ^2(c+d x) \tan ^4(c+d x) \, dx\\ &=\frac{a^2 \tan ^3(c+d x)}{3 d}+\frac{a b \sec (c+d x) \tan ^3(c+d x)}{2 d}-a^2 \int \tan ^2(c+d x) \, dx-\frac{1}{2} (3 a b) \int \sec (c+d x) \tan ^2(c+d x) \, dx+\frac{b^2 \operatorname{Subst}\left (\int x^4 \, dx,x,\tan (c+d x)\right )}{d}\\ &=-\frac{a^2 \tan (c+d x)}{d}-\frac{3 a b \sec (c+d x) \tan (c+d x)}{4 d}+\frac{a^2 \tan ^3(c+d x)}{3 d}+\frac{a b \sec (c+d x) \tan ^3(c+d x)}{2 d}+\frac{b^2 \tan ^5(c+d x)}{5 d}+a^2 \int 1 \, dx+\frac{1}{4} (3 a b) \int \sec (c+d x) \, dx\\ &=a^2 x+\frac{3 a b \tanh ^{-1}(\sin (c+d x))}{4 d}-\frac{a^2 \tan (c+d x)}{d}-\frac{3 a b \sec (c+d x) \tan (c+d x)}{4 d}+\frac{a^2 \tan ^3(c+d x)}{3 d}+\frac{a b \sec (c+d x) \tan ^3(c+d x)}{2 d}+\frac{b^2 \tan ^5(c+d x)}{5 d}\\ \end{align*}
Mathematica [B] time = 0.938164, size = 355, normalized size = 3.06 \[ \frac{\sec ^5(c+d x) \left (-80 a^2 \sin (c+d x)-160 a^2 \sin (3 (c+d x))-80 a^2 \sin (5 (c+d x))+60 a^2 c \cos (5 (c+d x))+60 a^2 d x \cos (5 (c+d x))-60 a b \sin (2 (c+d x))-150 a b \sin (4 (c+d x))-45 a b \cos (5 (c+d x)) \log \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )+45 a b \cos (5 (c+d x)) \log \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )+150 a \cos (c+d x) \left (4 a (c+d x)-3 b \log \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )+3 b \log \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )\right )+75 a \cos (3 (c+d x)) \left (4 a (c+d x)-3 b \log \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )+3 b \log \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )\right )+120 b^2 \sin (c+d x)-60 b^2 \sin (3 (c+d x))+12 b^2 \sin (5 (c+d x))\right )}{960 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.049, size = 164, normalized size = 1.4 \begin{align*}{\frac{{a}^{2} \left ( \tan \left ( dx+c \right ) \right ) ^{3}}{3\,d}}-{\frac{{a}^{2}\tan \left ( dx+c \right ) }{d}}+{a}^{2}x+{\frac{{a}^{2}c}{d}}+{\frac{ab \left ( \sin \left ( dx+c \right ) \right ) ^{5}}{2\,d \left ( \cos \left ( dx+c \right ) \right ) ^{4}}}-{\frac{ab \left ( \sin \left ( dx+c \right ) \right ) ^{5}}{4\,d \left ( \cos \left ( dx+c \right ) \right ) ^{2}}}-{\frac{ab \left ( \sin \left ( dx+c \right ) \right ) ^{3}}{4\,d}}-{\frac{3\,ab\sin \left ( dx+c \right ) }{4\,d}}+{\frac{3\,ab\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{4\,d}}+{\frac{{b}^{2} \left ( \sin \left ( dx+c \right ) \right ) ^{5}}{5\,d \left ( \cos \left ( dx+c \right ) \right ) ^{5}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.53085, size = 159, normalized size = 1.37 \begin{align*} \frac{24 \, b^{2} \tan \left (d x + c\right )^{5} + 40 \,{\left (\tan \left (d x + c\right )^{3} + 3 \, d x + 3 \, c - 3 \, \tan \left (d x + c\right )\right )} a^{2} + 15 \, a b{\left (\frac{2 \,{\left (5 \, \sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{4} - 2 \, \sin \left (d x + c\right )^{2} + 1} + 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) - 3 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )}}{120 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.808717, size = 393, normalized size = 3.39 \begin{align*} \frac{120 \, a^{2} d x \cos \left (d x + c\right )^{5} + 45 \, a b \cos \left (d x + c\right )^{5} \log \left (\sin \left (d x + c\right ) + 1\right ) - 45 \, a b \cos \left (d x + c\right )^{5} \log \left (-\sin \left (d x + c\right ) + 1\right ) - 2 \,{\left (75 \, a b \cos \left (d x + c\right )^{3} + 4 \,{\left (20 \, a^{2} - 3 \, b^{2}\right )} \cos \left (d x + c\right )^{4} - 30 \, a b \cos \left (d x + c\right ) - 4 \,{\left (5 \, a^{2} - 6 \, b^{2}\right )} \cos \left (d x + c\right )^{2} - 12 \, b^{2}\right )} \sin \left (d x + c\right )}{120 \, d \cos \left (d x + c\right )^{5}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (a + b \sec{\left (c + d x \right )}\right )^{2} \tan ^{4}{\left (c + d x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 2.33104, size = 297, normalized size = 2.56 \begin{align*} \frac{60 \,{\left (d x + c\right )} a^{2} + 45 \, a b \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1 \right |}\right ) - 45 \, a b \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1 \right |}\right ) + \frac{2 \,{\left (60 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{9} - 45 \, a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{9} - 320 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} + 210 \, a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} + 520 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} - 192 \, b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} - 320 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 210 \, a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 60 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 45 \, a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right )}^{5}}}{60 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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